C program to find sum of series 1 1 2 2 1 3 3 1 n n
#include<iostream.h>#include<conio.h>#include<math.h>
void main(){ clrscr(); double sum=0,a; int n,i; cout<<"1+1/2^2+1/3^3+.....+1/n^n"; cout<<"
Enter value of n:"; cin>>n;
for(i=1;i<=n;++i) { a=1/pow(i,i); sum+=a; }
cout<<"Sum="<<sum; getch();}
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